Cannot sudo a custom function in a zsh script

 If you're unable to run a custom function with `sudo` in a Zsh script, it's likely due to how Zsh interacts with `sudo` and function scoping. To execute a custom function with `sudo` in a Zsh script, you can use the `sudo` command to run the entire script or call the function explicitly with `sudo`. Here are two approaches:


1. **Run the Entire Script with `sudo`**:

   

   You can run the entire script with `sudo` to ensure that the custom function and any other commands within the script run with elevated privileges. For example:


   ```zsh

   #!/bin/zsh

   # This is your custom function

   my_function() {

       # Your custom function code

   }


   # Call your function with sudo

   sudo my_function


   # Other script code

   ```


   Save the script and then run it with `sudo`:


   ```bash

   sudo ./your_script.zsh

   ```


2. **Explicitly Call the Function with `sudo`**:


   If you want to call only the custom function with `sudo` while the rest of the script runs with regular privileges, you can do so explicitly:


   ```zsh

   #!/bin/zsh

   # This is your custom function

   my_function() {

       # Your custom function code

   }


   # Other script code


   # Call your function with sudo

   sudo my_function

   ```


   Save the script and run it without `sudo`. The custom function within the script will be called with elevated privileges:


   ```bash

   ./your_script.zsh

   ```


Choose the approach that best fits your script's requirements. The first approach runs the entire script with elevated privileges, while the second approach calls the custom function with `sudo` while keeping the rest of the script running with regular user privileges.

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